How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 35% antifreeze?To obtain a 35% antifreeze solution, □ gallon(s) of water should be added(Simplify your answer.)
Accepted Solution
A:
Assume that x gallon water is added: 35% antifreeze = 1 / (x + 1) = 0.35 1 = 0.35 x + 0.35 0.65 = 0.35(x) x = 1.857 gallons The answer is 1.89 gallons of waters should be added to 1 pure antifreeze to obtain a solution that is 35% antifreeze.